集合 s 包含从 1 到 n 的整数。不幸的是，因为数据错误，导致集合里面某一个数字复制了成了集合里面的另外一个数字的值，导致集合 丢失了一个数字 并且 有一个数字重复 。
给定一个数组 nums 代表了集合 S 发生错误后的结果。
请你找出重复出现的整数，再找到丢失的整数，将它们以数组的形式返回。
来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/set-mismatch
思路问题
hashmap计数 主要用getordefault方法初始化没有key的初始值（比直接if先判断再初始化方便多了）
水题
class Solution {
public int[] findErrorNums(int[] nums) {
int ans[] = new int[2], result;
HashMap<Integer, Integer> map = new HashMap<>();
for (int num : nums) {
map.put(num, map.getOrDefault(num, 0) + 1);
}
//从1开始到n
for (int num = 1; num < nums.length + 1; num++) {
result = map.getOrDefault(num, 0);
if (result == 2)
ans[0] = num;
else if (result == 0)
ans[1] = num;
}
return ans;
}
}
本文作者：Author： 寒光博客
文章标题：[leetcode] 645. 错误的集合
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版权说明：若无注明，本文皆为“Dxoca's blog （寒光博客）”原创，转载请保留文章出处。
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